ExamPlay Light Logo
Logg på

JEE MAIN - Physics (2021 - 16th March Morning Shift - No. 21)

In the figure given, the electric current flowing through the 5 k$$\Omega$$ resistor is 'x' mA.

JEE Main 2021 (Online) 16th March Morning Shift Physics - Current Electricity Question 199 English
The value of x to the nearest integer is ____________.
Svare
3

Forklaring

JEE Main 2021 (Online) 16th March Morning Shift Physics - Current Electricity Question 199 English Explanation
$$I = {{21} \over {5 + 1 + 1}}$$

$$ \therefore $$ I = 3 mA

Kommentarer (0)

Logg inn for å kommentere
Annonse
BrainBehindX Inc Logo
©2026; Drevet av BrainBehindX Inc